(x+3)(x^2+-2x-2)=0

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Solution for (x+3)(x^2+-2x-2)=0 equation: 


Simplifying
(x + 3)(x2 + -2x + -2) = 0

Reorder the terms:
(3 + x)(x2 + -2x + -2) = 0

Reorder the terms:
(3 + x)(-2 + -2x + x2) = 0

Multiply (3 + x) * (-2 + -2x + x2)
(3(-2 + -2x + x2) + x(-2 + -2x + x2)) = 0
((-2 * 3 + -2x * 3 + x2 * 3) + x(-2 + -2x + x2)) = 0
((-6 + -6x + 3x2) + x(-2 + -2x + x2)) = 0
(-6 + -6x + 3x2 + (-2 * x + -2x * x + x2 * x)) = 0
(-6 + -6x + 3x2 + (-2x + -2x2 + x3)) = 0

Reorder the terms:
(-6 + -6x + -2x + 3x2 + -2x2 + x3) = 0

Combine like terms: -6x + -2x = -8x
(-6 + -8x + 3x2 + -2x2 + x3) = 0

Combine like terms: 3x2 + -2x2 = 1x2
(-6 + -8x + 1x2 + x3) = 0

Solving
-6 + -8x + 1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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